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Relative projectile motion (one body)

Free notes · JEE Main Physics

Formulas

arel=a1a2=0\vec a_{rel} = \vec a_1 - \vec a_2 = 0

Zero relative acceleration

Worked example

For a fixed launch speed, the horizontal range of a projectile is maximum when the launch angle is:

  1. R = v0² sin 2θ / g
  2. R is maximum when sin 2θ = 1, i.e. 2θ = 90°, so θ = 45°

Answer: 45°